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200301100313 = 1693118311341
BaseRepresentation
bin1011101010001011100…
…0000011110100011001
3201011000022212011110212
42322202320003310121
511240204040202223
6232003403420505
720320435155326
oct2724270036431
9634008764425
10200301100313
1177a46827336
12329a0524735
1315b71813a42
1499a209db4d
155324aee278
hex2ea2e03d19

200301100313 has 4 divisors (see below), whose sum is σ = 200419413348. Its totient is φ = 200182787280.

The previous prime is 200301100273. The next prime is 200301100343. The reversal of 200301100313 is 313001103002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 54264770704 + 146036329609 = 232948^2 + 382147^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200301100313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200301100343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59153978 + ... + 59157363.

It is an arithmetic number, because the mean of its divisors is an integer number (50104853337).

Almost surely, 2200301100313 is an apocalyptic number.

It is an amenable number.

200301100313 is a deficient number, since it is larger than the sum of its proper divisors (118313035).

200301100313 is a wasteful number, since it uses less digits than its factorization.

200301100313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 118313034.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 200301100313 its reverse (313001103002), we get a palindrome (513302203315).

The spelling of 200301100313 in words is "two hundred billion, three hundred one million, one hundred thousand, three hundred thirteen".

Divisors: 1 1693 118311341 200301100313