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2003031330121 = 13914410297339
BaseRepresentation
bin11101001001011101111…
…110001000110101001001
321002111011200211101011001
4131021131332020311021
5230304202010030441
64132102504535001
7264466661246143
oct35113576106511
97074150741131
102003031330121
11702531a6aa98
1228424b181461
13116b67598133
146cd392cdc93
15371841ae731
hex1d25df88d49

2003031330121 has 4 divisors (see below), whose sum is σ = 2017441627600. Its totient is φ = 1988621032644.

The previous prime is 2003031330043. The next prime is 2003031330127. The reversal of 2003031330121 is 1210331303002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2003031330121 - 215 = 2003031297353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2003031330127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7205148531 + ... + 7205148808.

It is an arithmetic number, because the mean of its divisors is an integer number (504360406900).

Almost surely, 22003031330121 is an apocalyptic number.

It is an amenable number.

2003031330121 is a deficient number, since it is larger than the sum of its proper divisors (14410297479).

2003031330121 is a wasteful number, since it uses less digits than its factorization.

2003031330121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14410297478.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 2003031330121 its reverse (1210331303002), we get a palindrome (3213362633123).

The spelling of 2003031330121 in words is "two trillion, three billion, thirty-one million, three hundred thirty thousand, one hundred twenty-one".

Divisors: 1 139 14410297339 2003031330121