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20030414220251 = 28219709820129
BaseRepresentation
bin1001000110111101100011…
…01110010110101111011011
32121220220000000011222101122
410203132301232112233123
510111134242020022001
6110333502324235455
74135102223436641
oct443366156265733
977826000158348
1020030414220251
11642293a6a9956
1222b604123bb8b
13b23b24428b76
144d36976cd191
1524b085031b1b
hex1237b1b96bdb

20030414220251 has 4 divisors (see below), whose sum is σ = 20031124068600. Its totient is φ = 20029704371904.

The previous prime is 20030414220227. The next prime is 20030414220283. The reversal of 20030414220251 is 15202241403002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20030414220251 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20030414220251.

It is not an unprimeable number, because it can be changed into a prime (20030414220211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 354881846 + ... + 354938283.

It is an arithmetic number, because the mean of its divisors is an integer number (5007781017150).

Almost surely, 220030414220251 is an apocalyptic number.

20030414220251 is a deficient number, since it is larger than the sum of its proper divisors (709848349).

20030414220251 is an equidigital number, since it uses as much as digits as its factorization.

20030414220251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 709848348.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 20030414220251 its reverse (15202241403002), we get a palindrome (35232655623253).

The spelling of 20030414220251 in words is "twenty trillion, thirty billion, four hundred fourteen million, two hundred twenty thousand, two hundred fifty-one".

Divisors: 1 28219 709820129 20030414220251