Base | Representation |
---|---|
bin | 1001000110111101110011… |
… | …00010011100000111001011 |
3 | 2121220220100010212020112222 |
4 | 10203132321202130013023 |
5 | 10111140024100024001 |
6 | 110333523330124255 |
7 | 4135105404635123 |
oct | 443367142340713 |
9 | 77826303766488 |
10 | 20030545314251 |
11 | 64229a76a87aa |
12 | 22b607912068b |
13 | b23b45638594 |
14 | 4d36aac95c83 |
15 | 24b0917c961b |
hex | 1237b989c1cb |
20030545314251 has 4 divisors (see below), whose sum is σ = 20031405275952. Its totient is φ = 20029685352552.
The previous prime is 20030545314223. The next prime is 20030545314343. The reversal of 20030545314251 is 15241354503002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20030545314251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20030545314851) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 429945911 + ... + 429992496.
It is an arithmetic number, because the mean of its divisors is an integer number (5007851318988).
Almost surely, 220030545314251 is an apocalyptic number.
20030545314251 is a deficient number, since it is larger than the sum of its proper divisors (859961701).
20030545314251 is an equidigital number, since it uses as much as digits as its factorization.
20030545314251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 859961700.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 20030545314251 its reverse (15241354503002), we get a palindrome (35271899817253).
The spelling of 20030545314251 in words is "twenty trillion, thirty billion, five hundred forty-five million, three hundred fourteen thousand, two hundred fifty-one".
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