Base | Representation |
---|---|
bin | 11101001001100010010… |
… | …000101110010101100011 |
3 | 21002111100201021101122001 |
4 | 131021202100232111203 |
5 | 230304323421424303 |
6 | 4132113555424431 |
7 | 264501524133421 |
oct | 35114220562543 |
9 | 7074321241561 |
10 | 2003103311203 |
11 | 702569664495 |
12 | 28426b2b5117 |
13 | 116b7947b5a7 |
14 | 6cd44aaa111 |
15 | 3718a67c31d |
hex | 1d26242e563 |
2003103311203 has 4 divisors (see below), whose sum is σ = 2031316033968. Its totient is φ = 1974890588440.
The previous prime is 2003103311191. The next prime is 2003103311213. The reversal of 2003103311203 is 3021133013002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2003103311203 - 25 = 2003103311171 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2003103311213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14106361276 + ... + 14106361417.
It is an arithmetic number, because the mean of its divisors is an integer number (507829008492).
Almost surely, 22003103311203 is an apocalyptic number.
2003103311203 is a deficient number, since it is larger than the sum of its proper divisors (28212722765).
2003103311203 is an equidigital number, since it uses as much as digits as its factorization.
2003103311203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28212722764.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 2003103311203 its reverse (3021133013002), we get a palindrome (5024236324205).
The spelling of 2003103311203 in words is "two trillion, three billion, one hundred three million, three hundred eleven thousand, two hundred three".
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