200311001313 has 4 divisors (see below), whose sum is σ = 267081335088. Its totient is φ = 133540667540.

The previous prime is 200311001291. The next prime is 200311001351. The reversal of 200311001313 is 313100113002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200311001313 - 2¹³ = 200310993121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200311001292 and 200311001301.

It is not an unprimeable number, because it can be changed into a prime (200311001213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33385166883 + ... + 33385166888.

It is an arithmetic number, because the mean of its divisors is an integer number (66770333772).

Almost surely, 2^200311001313 is an apocalyptic number.

It is an amenable number.

200311001313 is a deficient number, since it is larger than the sum of its proper divisors (66770333775).

200311001313 is an equidigital number, since it uses as much as digits as its factorization.

200311001313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66770333774.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 200311001313 its reverse (313100113002), we get a palindrome (513411114315).

The spelling of 200311001313 in words is "two hundred billion, three hundred eleven million, one thousand, three hundred thirteen".