200311010031113 has 4 divisors (see below), whose sum is σ = 200311038580548. Its totient is φ = 200310981481680.

The previous prime is 200311010031089. The next prime is 200311010031149. The reversal of 200311010031113 is 311130010113002.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 42435479119504 + 157875530911609 = 6514252^2 + 12564853^2 .

It is a cyclic number.

It is not a de Polignac number, because 200311010031113 - 2¹⁴ = 200311010014729 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200311010031091 and 200311010031100.

It is not an unprimeable number, because it can be changed into a prime (200311010031193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4348595 + ... + 20482487.

It is an arithmetic number, because the mean of its divisors is an integer number (50077759645137).

Almost surely, 2^{200311010031113} is an apocalyptic number.

It is an amenable number.

200311010031113 is a deficient number, since it is larger than the sum of its proper divisors (28549435).

200311010031113 is a wasteful number, since it uses less digits than its factorization.

200311010031113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28549434.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 200311010031113 its reverse (311130010113002), we get a palindrome (511441020144115).

The spelling of 200311010031113 in words is "two hundred trillion, three hundred eleven billion, ten million, thirty-one thousand, one hundred thirteen".