200311212121 has 4 divisors (see below), whose sum is σ = 202183279632. Its totient is φ = 198439144612.

The previous prime is 200311212119. The next prime is 200311212193. The reversal of 200311212121 is 121212113002.

200311212121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200311212121 - 2¹ = 200311212119 is a prime.

It is a super-4 number, since 4×200311212121⁴ (a number of 46 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200311212095 and 200311212104.

It is not an unprimeable number, because it can be changed into a prime (200311212421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936033595 + ... + 936033808.

It is an arithmetic number, because the mean of its divisors is an integer number (50545819908).

Almost surely, 2^200311212121 is an apocalyptic number.

It is an amenable number.

200311212121 is a deficient number, since it is larger than the sum of its proper divisors (1872067511).

200311212121 is a wasteful number, since it uses less digits than its factorization.

200311212121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1872067510.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 200311212121 its reverse (121212113002), we get a palindrome (321523325123).

The spelling of 200311212121 in words is "two hundred billion, three hundred eleven million, two hundred twelve thousand, one hundred twenty-one".