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2003113121 = 8922506889
BaseRepresentation
bin111011101100101…
…0001010010100001
312011121012200121212
41313121101102201
513100244104441
6530433355505
7100432115642
oct16731212241
95147180555
102003113121
11938783599
1247aa08b95
1325bcc7349
141500696c9
15bacc9eeb
hex776514a1

2003113121 has 4 divisors (see below), whose sum is σ = 2025620100. Its totient is φ = 1980606144.

The previous prime is 2003113117. The next prime is 2003113129. The reversal of 2003113121 is 1213113002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 125104225 + 1878008896 = 11185^2 + 43336^2 .

It is a cyclic number.

It is not a de Polignac number, because 2003113121 - 22 = 2003113117 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2003113096 and 2003113105.

It is not an unprimeable number, because it can be changed into a prime (2003113129) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11253356 + ... + 11253533.

It is an arithmetic number, because the mean of its divisors is an integer number (506405025).

Almost surely, 22003113121 is an apocalyptic number.

It is an amenable number.

2003113121 is a deficient number, since it is larger than the sum of its proper divisors (22506979).

2003113121 is an equidigital number, since it uses as much as digits as its factorization.

2003113121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22506978.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 2003113121 is about 44756.1517671035. The cubic root of 2003113121 is about 1260.5744254523.

Adding to 2003113121 its reverse (1213113002), we get a palindrome (3216226123).

The spelling of 2003113121 in words is "two billion, three million, one hundred thirteen thousand, one hundred twenty-one".

Divisors: 1 89 22506889 2003113121