2003113202201 has 4 divisors (see below), whose sum is σ = 2028469065600. Its totient is φ = 1977757338804.

The previous prime is 2003113202177. The next prime is 2003113202203. The reversal of 2003113202201 is 1022023113002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2003113202201 is a prime.

It is a super-2 number, since 2×2003113202201² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2003113202201.

It is not an unprimeable number, because it can be changed into a prime (2003113202203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12677931581 + ... + 12677931738.

It is an arithmetic number, because the mean of its divisors is an integer number (507117266400).

Almost surely, 2^{2003113202201} is an apocalyptic number.

It is an amenable number.

2003113202201 is a deficient number, since it is larger than the sum of its proper divisors (25355863399).

2003113202201 is an equidigital number, since it uses as much as digits as its factorization.

2003113202201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25355863398.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 2003113202201 its reverse (1022023113002), we get a palindrome (3025136315203).

The spelling of 2003113202201 in words is "two trillion, three billion, one hundred thirteen million, two hundred two thousand, two hundred one".