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20031200133121 = 84503237047207
BaseRepresentation
bin1001000110111111000001…
…00100011000000000000001
32121220222000210000111011201
410203133200210120000001
510111142344213224441
6110334112321141201
74135130545542052
oct443374044300001
977828023014151
1020031200133121
116423203298921
1222b622048a801
13b23c1b1b8a78
144d372dc2c729
1524b0ce024c31
hex1237e0918001

20031200133121 has 4 divisors (see below), whose sum is σ = 20031437264832. Its totient is φ = 20030963001412.

The previous prime is 20031200133101. The next prime is 20031200133149. The reversal of 20031200133121 is 12133100213002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20031200133121 - 211 = 20031200131073 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20031200133101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 118439101 + ... + 118608106.

It is an arithmetic number, because the mean of its divisors is an integer number (5007859316208).

Almost surely, 220031200133121 is an apocalyptic number.

It is an amenable number.

20031200133121 is a deficient number, since it is larger than the sum of its proper divisors (237131711).

20031200133121 is an equidigital number, since it uses as much as digits as its factorization.

20031200133121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 237131710.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 20031200133121 its reverse (12133100213002), we get a palindrome (32164300346123).

The spelling of 20031200133121 in words is "twenty trillion, thirty-one billion, two hundred million, one hundred thirty-three thousand, one hundred twenty-one".

Divisors: 1 84503 237047207 20031200133121