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200312133401 = 434658421707
BaseRepresentation
bin1011101010001110001…
…0001001011100011001
3201011001002121201000202
42322203202021130121
511240214401232101
6232004440111545
720320631016632
oct2724342113431
9634032551022
10200312133401
1177a51a82696
12329a41655b5
1315b73ba78b3
1499a3732889
155325a7d36b
hex2ea3889719

200312133401 has 4 divisors (see below), whose sum is σ = 204970555152. Its totient is φ = 195653711652.

The previous prime is 200312133389. The next prime is 200312133433. The reversal of 200312133401 is 104331213002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200312133401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200312133601) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2329210811 + ... + 2329210896.

It is an arithmetic number, because the mean of its divisors is an integer number (51242638788).

Almost surely, 2200312133401 is an apocalyptic number.

It is an amenable number.

200312133401 is a deficient number, since it is larger than the sum of its proper divisors (4658421751).

200312133401 is an equidigital number, since it uses as much as digits as its factorization.

200312133401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4658421750.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 200312133401 its reverse (104331213002), we get a palindrome (304643346403).

The spelling of 200312133401 in words is "two hundred billion, three hundred twelve million, one hundred thirty-three thousand, four hundred one".

Divisors: 1 43 4658421707 200312133401