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2003122321113 = 32329030758277
BaseRepresentation
bin11101001001100011011…
…001001111011011011001
321002111102001001012022210
4131021203121033123121
5230304343303233423
64132115515105333
7264502144540044
oct35114331173331
97074361035283
102003122321113
11702579368961
12284275742249
13116b803a6164
146cd47417c5b
153718c184b93
hex1d26364f6d9

2003122321113 has 8 divisors (see below), whose sum is σ = 2786952794688. Its totient is φ = 1277353364144.

The previous prime is 2003122321097. The next prime is 2003122321129. The reversal of 2003122321113 is 3111232213002.

It is an interprime number because it is at equal distance from previous prime (2003122321097) and next prime (2003122321129).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2003122321113 - 24 = 2003122321097 is a prime.

It is a super-2 number, since 2×20031223211132 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 2003122321113.

It is not an unprimeable number, because it can be changed into a prime (2003122321133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14515379070 + ... + 14515379207.

It is an arithmetic number, because the mean of its divisors is an integer number (348369099336).

Almost surely, 22003122321113 is an apocalyptic number.

2003122321113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

2003122321113 is a deficient number, since it is larger than the sum of its proper divisors (783830473575).

2003122321113 is a wasteful number, since it uses less digits than its factorization.

2003122321113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29030758303.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 2003122321113 its reverse (3111232213002), we get a palindrome (5114354534115).

The spelling of 2003122321113 in words is "two trillion, three billion, one hundred twenty-two million, three hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 3 23 69 29030758277 87092274831 667707440371 2003122321113