Base | Representation |
---|---|
bin | 10010101001111101… |
… | …010110011000001011 |
3 | 1220201000102112022220 |
4 | 102221331112120023 |
5 | 312011003114011 |
6 | 13111404145123 |
7 | 1306252151562 |
oct | 225175263013 |
9 | 56630375286 |
10 | 20031301131 |
11 | 854a169026 |
12 | 3a705381a3 |
13 | 1b73016c0a |
14 | d80512bd9 |
15 | 7c38a0506 |
hex | 4a9f5660b |
20031301131 has 4 divisors (see below), whose sum is σ = 26708401512. Its totient is φ = 13354200752.
The previous prime is 20031301117. The next prime is 20031301183. The reversal of 20031301131 is 13110313002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20031301131 - 25 = 20031301099 is a prime.
It is a super-2 number, since 2×200313011312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 20031301131.
It is not an unprimeable number, because it can be changed into a prime (20031300131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3338550186 + ... + 3338550191.
It is an arithmetic number, because the mean of its divisors is an integer number (6677100378).
Almost surely, 220031301131 is an apocalyptic number.
20031301131 is a deficient number, since it is larger than the sum of its proper divisors (6677100381).
20031301131 is an equidigital number, since it uses as much as digits as its factorization.
20031301131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6677100380.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 20031301131 its reverse (13110313002), we get a palindrome (33141614133).
The spelling of 20031301131 in words is "twenty billion, thirty-one million, three hundred one thousand, one hundred thirty-one".
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