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2003131212331 = 4574383219283
BaseRepresentation
bin11101001001100011111…
…011001010001000101011
321002111102122202220210011
4131021203323022020223
5230304403042243311
64132120433432351
7264502313241004
oct35114373121053
97074378686704
102003131212331
11702583390a77
1228427870b6b7
13116b8219a132
146cd486901ab
153718cd3e321
hex1d263eca22b

2003131212331 has 4 divisors (see below), whose sum is σ = 2007514432072. Its totient is φ = 1998747992592.

The previous prime is 2003131212307. The next prime is 2003131212337. The reversal of 2003131212331 is 1332121313002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2003131212331 - 221 = 2003129115179 is a prime.

It is a super-2 number, since 2×20031312123312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2003131212337) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2191609185 + ... + 2191610098.

It is an arithmetic number, because the mean of its divisors is an integer number (501878608018).

Almost surely, 22003131212331 is an apocalyptic number.

2003131212331 is a deficient number, since it is larger than the sum of its proper divisors (4383219741).

2003131212331 is an equidigital number, since it uses as much as digits as its factorization.

2003131212331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4383219740.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 2003131212331 its reverse (1332121313002), we get a palindrome (3335252525333).

The spelling of 2003131212331 in words is "two trillion, three billion, one hundred thirty-one million, two hundred twelve thousand, three hundred thirty-one".

Divisors: 1 457 4383219283 2003131212331