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200313314011 = 304883657017
BaseRepresentation
bin1011101010001110011…
…0101001101011011011
3201011001011211200112001
42322203212221223123
511240220202022021
6232004521301431
720320644034636
oct2724346515333
9634034750461
10200313314011
1177a527096a8
12329a4634877
1315b741cc095
1499a395cc1d
155325c13091
hex2ea39a9adb

200313314011 has 4 divisors (see below), whose sum is σ = 200314275912. Its totient is φ = 200312352112.

The previous prime is 200313313999. The next prime is 200313314021. The reversal of 200313314011 is 110413313002.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 200313314011 - 25 = 200313313979 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 200313314011.

It is not an unprimeable number, because it can be changed into a prime (200313314021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23626 + ... + 633391.

It is an arithmetic number, because the mean of its divisors is an integer number (50078568978).

Almost surely, 2200313314011 is an apocalyptic number.

200313314011 is a deficient number, since it is larger than the sum of its proper divisors (961901).

200313314011 is an equidigital number, since it uses as much as digits as its factorization.

200313314011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 961900.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 200313314011 its reverse (110413313002), we get a palindrome (310726627013).

The spelling of 200313314011 in words is "two hundred billion, three hundred thirteen million, three hundred fourteen thousand, eleven".

Divisors: 1 304883 657017 200313314011