Search a number
-
+
200320103121 = 366773367707
BaseRepresentation
bin1011101010010000000…
…0100011001011010001
3201011001122121121102120
42322210000203023101
511240223421244441
6232005323004453
720321055532155
oct2724400431321
9634048547376
10200320103121
1177a56526436
12329a6969729
1315b757382c8
1499a4809065
155326604966
hex2ea40232d1

200320103121 has 4 divisors (see below), whose sum is σ = 267093470832. Its totient is φ = 133546735412.

The previous prime is 200320103051. The next prime is 200320103131. The reversal of 200320103121 is 121301023002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200320103121 - 214 = 200320086737 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 200320103121.

It is not an unprimeable number, because it can be changed into a prime (200320103131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33386683851 + ... + 33386683856.

It is an arithmetic number, because the mean of its divisors is an integer number (66773367708).

Almost surely, 2200320103121 is an apocalyptic number.

It is an amenable number.

200320103121 is a deficient number, since it is larger than the sum of its proper divisors (66773367711).

200320103121 is an equidigital number, since it uses as much as digits as its factorization.

200320103121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66773367710.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 200320103121 its reverse (121301023002), we get a palindrome (321621126123).

The spelling of 200320103121 in words is "two hundred billion, three hundred twenty million, one hundred three thousand, one hundred twenty-one".

Divisors: 1 3 66773367707 200320103121