Base | Representation |
---|---|
bin | 11101001001101001011… |
… | …010001100000111101001 |
3 | 21002111200001221001102010 |
4 | 131021221122030013221 |
5 | 230310100121424001 |
6 | 4132133522030133 |
7 | 264504511350564 |
oct | 35115132140751 |
9 | 7074601831363 |
10 | 2003223233001 |
11 | 702620322511 |
12 | 2842a34a8349 |
13 | 116b98278a33 |
14 | 6cd569a54db |
15 | 37195e698d6 |
hex | 1d26968c1e9 |
2003223233001 has 8 divisors (see below), whose sum is σ = 2671316200384. Its totient is φ = 1335306210480.
The previous prime is 2003223232999. The next prime is 2003223233009. The reversal of 2003223233001 is 1003323223002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2003223233001 - 21 = 2003223232999 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2003223233009) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43959646 + ... + 44005191.
It is an arithmetic number, because the mean of its divisors is an integer number (333914525048).
Almost surely, 22003223233001 is an apocalyptic number.
It is an amenable number.
2003223233001 is a deficient number, since it is larger than the sum of its proper divisors (668092967383).
2003223233001 is an equidigital number, since it uses as much as digits as its factorization.
2003223233001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87972431.
The product of its (nonzero) digits is 1296, while the sum is 21.
Adding to 2003223233001 its reverse (1003323223002), we get a palindrome (3006546456003).
Subtracting from 2003223233001 its reverse (1003323223002), we obtain a palindrome (999900009999).
The spelling of 2003223233001 in words is "two trillion, three billion, two hundred twenty-three million, two hundred thirty-three thousand, one".
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