Base | Representation |
---|---|
bin | 101101100011000101011011… |
… | …111111111001011111111011 |
3 | 222021021200222011222202001121 |
4 | 231203011123333321133323 |
5 | 202224043213430124404 |
6 | 1550015100121130111 |
7 | 60123603326515600 |
oct | 5543053377713773 |
9 | 867250864882047 |
10 | 200323113129979 |
11 | 58913611a49264 |
12 | 1a573b65329937 |
13 | 87a1508739858 |
14 | 37679946a26a7 |
15 | 1825ce5957e54 |
hex | b6315bff97fb |
200323113129979 has 6 divisors (see below), whose sum is σ = 233028927518604. Its totient is φ = 171705525539940.
The previous prime is 200323113129973. The next prime is 200323113130111. The reversal of 200323113129979 is 979921311323002.
It is not a de Polignac number, because 200323113129979 - 211 = 200323113127931 is a prime.
It is a super-2 number, since 2×2003231131299792 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (200323113129973) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 2044113399237 + ... + 2044113399334.
It is an arithmetic number, because the mean of its divisors is an integer number (38838154586434).
Almost surely, 2200323113129979 is an apocalyptic number.
200323113129979 is a deficient number, since it is larger than the sum of its proper divisors (32705814388625).
200323113129979 is an equidigital number, since it uses as much as digits as its factorization.
200323113129979 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4088226798585 (or 4088226798578 counting only the distinct ones).
The product of its (nonzero) digits is 1102248, while the sum is 52.
The spelling of 200323113129979 in words is "two hundred trillion, three hundred twenty-three billion, one hundred thirteen million, one hundred twenty-nine thousand, nine hundred seventy-nine".
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