Search a number
-
+
200323115 = 540279949
BaseRepresentation
bin10111111000010…
…11000000101011
3111221221110122122
423330023000223
5402240314430
631513341455
74651501256
oct1374130053
9457843578
10200323115
11a30937a3
125710788b
133266b3b5
141c86809d
15128beee5
hexbf0b02b

200323115 has 8 divisors (see below), whose sum is σ = 240471600. Its totient is φ = 160202592.

The previous prime is 200323091. The next prime is 200323127. The reversal of 200323115 is 511323002.

200323115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 200323115 - 212 = 200319019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200323093 and 200323102.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15161 + ... + 25109.

It is an arithmetic number, because the mean of its divisors is an integer number (30058950).

Almost surely, 2200323115 is an apocalyptic number.

200323115 is a deficient number, since it is larger than the sum of its proper divisors (40148485).

200323115 is an equidigital number, since it uses as much as digits as its factorization.

200323115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13981.

The product of its (nonzero) digits is 180, while the sum is 17.

The square root of 200323115 is about 14153.5548538168. The cubic root of 200323115 is about 585.1183095267.

Adding to 200323115 its reverse (511323002), we get a palindrome (711646117).

The spelling of 200323115 in words is "two hundred million, three hundred twenty-three thousand, one hundred fifteen".

Divisors: 1 5 4027 9949 20135 49745 40064623 200323115