Base | Representation |
---|---|
bin | 11101001001101111111… |
… | …001100110110010110011 |
3 | 21002111221122211200210002 |
4 | 131021233321212302303 |
5 | 230310311011211034 |
6 | 4132152412100215 |
7 | 264510303105461 |
oct | 35115771466263 |
9 | 7074848750702 |
10 | 2003332132019 |
11 | 7026768419a9 |
12 | 284313a6466b |
13 | 116bb49b6c1a |
14 | 6cd67231831 |
15 | 371a07cae7e |
hex | 1d26fe66cb3 |
2003332132019 has 8 divisors (see below), whose sum is σ = 2004209792832. Its totient is φ = 2002454657280.
The previous prime is 2003332132003. The next prime is 2003332132027. The reversal of 2003332132019 is 9102312333002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2003332132019 - 24 = 2003332132003 is a prime.
It is a super-2 number, since 2×20033321320192 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2003332131982 and 2003332132000.
It is not an unprimeable number, because it can be changed into a prime (2003332132519) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24176579 + ... + 24259299.
It is an arithmetic number, because the mean of its divisors is an integer number (250526224104).
Almost surely, 22003332132019 is an apocalyptic number.
2003332132019 is a deficient number, since it is larger than the sum of its proper divisors (877660813).
2003332132019 is an equidigital number, since it uses as much as digits as its factorization.
2003332132019 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 93037.
The product of its (nonzero) digits is 5832, while the sum is 29.
The spelling of 2003332132019 in words is "two trillion, three billion, three hundred thirty-two million, one hundred thirty-two thousand, nineteen".
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