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200333222113 = 897122331203
BaseRepresentation
bin1011101010010011001…
…0100110000011100001
3201011002120022010022011
42322210302212003201
511240240301101423
6232010512112521
720321305202023
oct2724462460341
9634076263264
10200333222113
1177a62976982
12329ab235741
1315b7837c71b
1499a6462013
155327846b0d
hex2ea4ca60e1

200333222113 has 4 divisors (see below), whose sum is σ = 200355562288. Its totient is φ = 200310881940.

The previous prime is 200333222101. The next prime is 200333222129. The reversal of 200333222113 is 311222333002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200333222113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200333226113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11156631 + ... + 11174572.

It is an arithmetic number, because the mean of its divisors is an integer number (50088890572).

Almost surely, 2200333222113 is an apocalyptic number.

It is an amenable number.

200333222113 is a deficient number, since it is larger than the sum of its proper divisors (22340175).

200333222113 is an equidigital number, since it uses as much as digits as its factorization.

200333222113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22340174.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 200333222113 its reverse (311222333002), we get a palindrome (511555555115).

The spelling of 200333222113 in words is "two hundred billion, three hundred thirty-three million, two hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 8971 22331203 200333222113