200333313000113 has 4 divisors (see below), whose sum is σ = 203617465672308. Its totient is φ = 197049160327920.

The previous prime is 200333313000091. The next prime is 200333313000127. The reversal of 200333313000113 is 311000313333002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 71147993495329 + 129185319504784 = 8434927^2 + 11365972^2 .

It is a cyclic number.

It is not a de Polignac number, because 200333313000113 - 2¹⁸ = 200333312737969 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (200333313000173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1642076336006 + ... + 1642076336127.

It is an arithmetic number, because the mean of its divisors is an integer number (50904366418077).

Almost surely, 2^{200333313000113} is an apocalyptic number.

It is an amenable number.

200333313000113 is a deficient number, since it is larger than the sum of its proper divisors (3284152672195).

200333313000113 is an equidigital number, since it uses as much as digits as its factorization.

200333313000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3284152672194.

The product of its (nonzero) digits is 1458, while the sum is 23.

Adding to 200333313000113 its reverse (311000313333002), we get a palindrome (511333626333115).

The spelling of 200333313000113 in words is "two hundred trillion, three hundred thirty-three billion, three hundred thirteen million, one hundred thirteen", and thus it is an aban number.