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20033334121 = 23871014527
BaseRepresentation
bin10010101010000101…
…000110101101101001
31220201011020211001211
4102222011012231221
5312012013142441
613111515513121
71306305346633
oct225205065551
956634224054
1020033334121
118550327489
123a711587a1
131b73579378
14d808c1a53
157c3b52a81
hex4aa146b69

20033334121 has 4 divisors (see below), whose sum is σ = 20904348672. Its totient is φ = 19162319572.

The previous prime is 20033334091. The next prime is 20033334149. The reversal of 20033334121 is 12143333002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20033334121 - 29 = 20033333609 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20033334092 and 20033334101.

It is not an unprimeable number, because it can be changed into a prime (20033334221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435507241 + ... + 435507286.

It is an arithmetic number, because the mean of its divisors is an integer number (5226087168).

Almost surely, 220033334121 is an apocalyptic number.

It is an amenable number.

20033334121 is a deficient number, since it is larger than the sum of its proper divisors (871014551).

20033334121 is an equidigital number, since it uses as much as digits as its factorization.

20033334121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 871014550.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 20033334121 its reverse (12143333002), we get a palindrome (32176667123).

The spelling of 20033334121 in words is "twenty billion, thirty-three million, three hundred thirty-four thousand, one hundred twenty-one".

Divisors: 1 23 871014527 20033334121