Base | Representation |
---|---|
bin | 1001000111000011010100… |
… | …11011101111100110101001 |
3 | 2121221011222222022201100020 |
4 | 10203201222123233212221 |
5 | 10111212113330020223 |
6 | 110335134024431053 |
7 | 4135242062630331 |
oct | 443415233574651 |
9 | 77834888281306 |
10 | 20033513126313 |
11 | 642418a983945 |
12 | 22b6767018489 |
13 | b241c945ccab |
14 | 4d38ad0c00c1 |
15 | 24b1b71111e3 |
hex | 12386a6ef9a9 |
20033513126313 has 4 divisors (see below), whose sum is σ = 26711350835088. Its totient is φ = 13355675417540.
The previous prime is 20033513126299. The next prime is 20033513126323. The reversal of 20033513126313 is 31362131533002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 20033513126313 - 28 = 20033513126057 is a prime.
It is not an unprimeable number, because it can be changed into a prime (20033513126323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3338918854383 + ... + 3338918854388.
It is an arithmetic number, because the mean of its divisors is an integer number (6677837708772).
Almost surely, 220033513126313 is an apocalyptic number.
It is an amenable number.
20033513126313 is a deficient number, since it is larger than the sum of its proper divisors (6677837708775).
20033513126313 is an equidigital number, since it uses as much as digits as its factorization.
20033513126313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6677837708774.
The product of its (nonzero) digits is 29160, while the sum is 33.
Adding to 20033513126313 its reverse (31362131533002), we get a palindrome (51395644659315).
The spelling of 20033513126313 in words is "twenty trillion, thirty-three billion, five hundred thirteen million, one hundred twenty-six thousand, three hundred thirteen".
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