2003401203 has 4 divisors (see below), whose sum is σ = 2671201608. Its totient is φ = 1335600800.

The previous prime is 2003401199. The next prime is 2003401241. The reversal of 2003401203 is 3021043002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2003401203 - 2² = 2003401199 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2003401243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333900198 + ... + 333900203.

It is an arithmetic number, because the mean of its divisors is an integer number (667800402).

Almost surely, 2^2003401203 is an apocalyptic number.

2003401203 is a deficient number, since it is larger than the sum of its proper divisors (667800405).

2003401203 is an equidigital number, since it uses as much as digits as its factorization.

2003401203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 667800404.

The product of its (nonzero) digits is 144, while the sum is 15.

The square root of 2003401203 is about 44759.3700022688. The cubic root of 2003401203 is about 1260.6348532917.

Adding to 2003401203 its reverse (3021043002), we get a palindrome (5024444205).

The spelling of 2003401203 in words is "two billion, three million, four hundred one thousand, two hundred three".