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200340131 = 1022319597
BaseRepresentation
bin10111111000011…
…11001010100011
3111221222022222212
423330033022203
5402241341011
631513552335
74651602005
oct1374171243
9457868885
10200340131
11a30a5562
12571156ab
1332676074
141c870375
15128c508b
hexbf0f2a3

200340131 has 4 divisors (see below), whose sum is σ = 200369952. Its totient is φ = 200310312.

The previous prime is 200340113. The next prime is 200340137. The reversal of 200340131 is 131043002.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200340131 is a prime.

It is a super-2 number, since 2×2003401312 = 80272336178194322, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200340137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 425 + ... + 20021.

It is an arithmetic number, because the mean of its divisors is an integer number (50092488).

Almost surely, 2200340131 is an apocalyptic number.

200340131 is a deficient number, since it is larger than the sum of its proper divisors (29821).

200340131 is a wasteful number, since it uses less digits than its factorization.

200340131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 29820.

The product of its (nonzero) digits is 72, while the sum is 14.

The square root of 200340131 is about 14154.1559621194. The cubic root of 200340131 is about 585.1348762474.

Adding to 200340131 its reverse (131043002), we get a palindrome (331383133).

The spelling of 200340131 in words is "two hundred million, three hundred forty thousand, one hundred thirty-one".

Divisors: 1 10223 19597 200340131