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2003431314403 = 6433115756321
BaseRepresentation
bin11101001001110101110…
…011111101001111100011
321002112012120110200102201
4131021311303331033203
5230311011404030103
64132210313554031
7264512616124111
oct35116563751743
97075176420381
102003431314403
11702717825112
12284341115917
13116bcc40251c
146cd7648cab1
15371a936d51d
hex1d275cfd3e3

2003431314403 has 4 divisors (see below), whose sum is σ = 2006547071368. Its totient is φ = 2000315557440.

The previous prime is 2003431314389. The next prime is 2003431314421. The reversal of 2003431314403 is 3044131343002.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2003431314403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2003431314103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1557877518 + ... + 1557878803.

It is an arithmetic number, because the mean of its divisors is an integer number (501636767842).

Almost surely, 22003431314403 is an apocalyptic number.

2003431314403 is a deficient number, since it is larger than the sum of its proper divisors (3115756965).

2003431314403 is an equidigital number, since it uses as much as digits as its factorization.

2003431314403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3115756964.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 2003431314403 its reverse (3044131343002), we get a palindrome (5047562657405).

The spelling of 2003431314403 in words is "two trillion, three billion, four hundred thirty-one million, three hundred fourteen thousand, four hundred three".

Divisors: 1 643 3115756321 2003431314403