2003441113 has 4 divisors (see below), whose sum is σ = 2004232720. Its totient is φ = 2002649508.

The previous prime is 2003441107. The next prime is 2003441159. The reversal of 2003441113 is 3111443002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2003441113 - 2¹⁷ = 2003310041 is a prime.

It is a super-3 number, since 3×2003441113³ (a number of 29 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2003441173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 391995 + ... + 397072.

It is an arithmetic number, because the mean of its divisors is an integer number (501058180).

Almost surely, 2^2003441113 is an apocalyptic number.

It is an amenable number.

2003441113 is a deficient number, since it is larger than the sum of its proper divisors (791607).

2003441113 is an equidigital number, since it uses as much as digits as its factorization.

2003441113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 791606.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 2003441113 is about 44759.8158284862. The cubic root of 2003441113 is about 1260.6432243231.

Adding to 2003441113 its reverse (3111443002), we get a palindrome (5114884115).

The spelling of 2003441113 in words is "two billion, three million, four hundred forty-one thousand, one hundred thirteen".