2004021300115 has 8 divisors (see below), whose sum is σ = 2405176312320. Its totient is φ = 1602983205312.

The previous prime is 2004021300107. The next prime is 2004021300157. The reversal of 2004021300115 is 5110031204002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2004021300115 - 2³ = 2004021300107 is a prime.

It is a super-2 number, since 2×2004021300115² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2004021300092 and 2004021300101.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29191635 + ... + 29260204.

It is an arithmetic number, because the mean of its divisors is an integer number (300647039040).

Almost surely, 2^{2004021300115} is an apocalyptic number.

2004021300115 is a deficient number, since it is larger than the sum of its proper divisors (401155012205).

2004021300115 is an equidigital number, since it uses as much as digits as its factorization.

2004021300115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58458701.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 2004021300115 its reverse (5110031204002), we get a palindrome (7114052504117).

The spelling of 2004021300115 in words is "two trillion, four billion, twenty-one million, three hundred thousand, one hundred fifteen".