2004125113 has 4 divisors (see below), whose sum is σ = 2005823268. Its totient is φ = 2002426960.

The previous prime is 2004125089. The next prime is 2004125143. The reversal of 2004125113 is 3115214002.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1705111849 + 299013264 = 41293^2 + 17292^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2004125113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2004125143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 847306 + ... + 849667.

It is an arithmetic number, because the mean of its divisors is an integer number (501455817).

Almost surely, 2^2004125113 is an apocalyptic number.

It is an amenable number.

2004125113 is a deficient number, since it is larger than the sum of its proper divisors (1698155).

2004125113 is a wasteful number, since it uses less digits than its factorization.

2004125113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1698154.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 2004125113 is about 44767.4559585420. The cubic root of 2004125113 is about 1260.7866744845.

Adding to 2004125113 its reverse (3115214002), we get a palindrome (5119339115).

Subtracting 2004125113 from its reverse (3115214002), we obtain a square (1111088889 = 33333²).

It can be divided in two parts, 20041 and 25113, that added together give a palindrome (45154).

The spelling of 2004125113 in words is "two billion, four million, one hundred twenty-five thousand, one hundred thirteen".