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200425433 = 13193792141
BaseRepresentation
bin10111111001000…
…11111111011001
3111222010200000012
423330203333121
5402302103213
631515451305
74652405465
oct1374437731
9458120005
10200425433
11a315365a
1257156b35
13326a5b40
141c8934a5
15128e04a8
hexbf23fd9

200425433 has 16 divisors (see below), whose sum is σ = 227908800. Its totient is φ = 174726720.

The previous prime is 200425429. The next prime is 200425453. The reversal of 200425433 is 334524002.

It is a cyclic number.

It is not a de Polignac number, because 200425433 - 22 = 200425429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200425399 and 200425408.

It is not an unprimeable number, because it can be changed into a prime (200425453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 92543 + ... + 94683.

It is an arithmetic number, because the mean of its divisors is an integer number (14244300).

Almost surely, 2200425433 is an apocalyptic number.

It is an amenable number.

200425433 is a deficient number, since it is larger than the sum of its proper divisors (27483367).

200425433 is a wasteful number, since it uses less digits than its factorization.

200425433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2552.

The product of its (nonzero) digits is 2880, while the sum is 23.

The square root of 200425433 is about 14157.1689613425. The cubic root of 200425433 is about 585.2179118538.

Adding to 200425433 its reverse (334524002), we get a palindrome (534949435).

The spelling of 200425433 in words is "two hundred million, four hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 13 19 247 379 2141 4927 7201 27833 40679 93613 528827 811439 10548707 15417341 200425433