200441234121113 has 4 divisors (see below), whose sum is σ = 200720011916160. Its totient is φ = 200162456326068.

The previous prime is 200441234121109. The next prime is 200441234121209. The reversal of 200441234121113 is 311121432144002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200441234121113 - 2² = 200441234121109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (200441234121413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139388896445 + ... + 139388897882.

It is an arithmetic number, because the mean of its divisors is an integer number (50180002979040).

Almost surely, 2^{200441234121113} is an apocalyptic number.

It is an amenable number.

200441234121113 is a deficient number, since it is larger than the sum of its proper divisors (278777795047).

200441234121113 is an equidigital number, since it uses as much as digits as its factorization.

200441234121113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 278777795046.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 200441234121113 its reverse (311121432144002), we get a palindrome (511562666265115).

The spelling of 200441234121113 in words is "two hundred trillion, four hundred forty-one billion, two hundred thirty-four million, one hundred twenty-one thousand, one hundred thirteen".