200442213242131 has 4 divisors (see below), whose sum is σ = 229076815133872. Its totient is φ = 171807611350392.

The previous prime is 200442213242023. The next prime is 200442213242149. The reversal of 200442213242131 is 131242312244002.

200442213242131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200442213242131 - 2¹⁵ = 200442213209363 is a prime.

It is a super-2 number, since 2×200442213242131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200442213242093 and 200442213242102.

It is not an unprimeable number, because it can be changed into a prime (200442213842131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14317300945860 + ... + 14317300945873.

It is an arithmetic number, because the mean of its divisors is an integer number (57269203783468).

Almost surely, 2^{200442213242131} is an apocalyptic number.

200442213242131 is a deficient number, since it is larger than the sum of its proper divisors (28634601891741).

200442213242131 is an equidigital number, since it uses as much as digits as its factorization.

200442213242131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28634601891740.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 200442213242131 its reverse (131242312244002), we get a palindrome (331684525486133).

The spelling of 200442213242131 in words is "two hundred trillion, four hundred forty-two billion, two hundred thirteen million, two hundred forty-two thousand, one hundred thirty-one".