Base | Representation |
---|---|
bin | 11101001011110001001… |
… | …011101110100110011011 |
3 | 21002201112211012220002211 |
4 | 131023301023232212123 |
5 | 230324231243042301 |
6 | 4133151533335551 |
7 | 264615121311121 |
oct | 35136113564633 |
9 | 7081484186084 |
10 | 2005501143451 |
11 | 70358a126333 |
12 | 28481a3375b7 |
13 | 11716c188640 |
14 | 6d0d1323911 |
15 | 3727ae26051 |
hex | 1d2f12ee99b |
2005501143451 has 16 divisors (see below), whose sum is σ = 2165244681600. Its totient is φ = 1846544698368.
The previous prime is 2005501143413. The next prime is 2005501143469. The reversal of 2005501143451 is 1543411055002.
It is a cyclic number.
It is not a de Polignac number, because 2005501143451 - 229 = 2004964272539 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2005501140451) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9489390 + ... + 9698428.
It is an arithmetic number, because the mean of its divisors is an integer number (135327792600).
Almost surely, 22005501143451 is an apocalyptic number.
2005501143451 is a deficient number, since it is larger than the sum of its proper divisors (159743538149).
2005501143451 is a wasteful number, since it uses less digits than its factorization.
2005501143451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 210918.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 2005501143451 its reverse (1543411055002), we get a palindrome (3548912198453).
The spelling of 2005501143451 in words is "two trillion, five billion, five hundred one million, one hundred forty-three thousand, four hundred fifty-one".
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