Base | Representation |
---|---|
bin | 1001000111101100010001… |
… | …11110001100101011100011 |
3 | 2122000021202022002102212201 |
4 | 10203312020332030223203 |
5 | 10112042131034430032 |
6 | 110353211502234031 |
7 | 4136650664623351 |
oct | 443661076145343 |
9 | 78007668072781 |
10 | 20055500311267 |
11 | 6432543097383 |
12 | 22baa82585917 |
13 | b262c1745cc5 |
14 | 4d49972867d1 |
15 | 24ba5255c8e7 |
hex | 123d88f8cae3 |
20055500311267 has 4 divisors (see below), whose sum is σ = 20058792962296. Its totient is φ = 20052207660240.
The previous prime is 20055500311241. The next prime is 20055500311271. The reversal of 20055500311267 is 76211300555002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 20055500311267 - 223 = 20055491922659 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (20055500311367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1646316378 + ... + 1646328559.
It is an arithmetic number, because the mean of its divisors is an integer number (5014698240574).
Almost surely, 220055500311267 is an apocalyptic number.
20055500311267 is a deficient number, since it is larger than the sum of its proper divisors (3292651029).
20055500311267 is an equidigital number, since it uses as much as digits as its factorization.
20055500311267 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3292651028.
The product of its (nonzero) digits is 63000, while the sum is 37.
Adding to 20055500311267 its reverse (76211300555002), we get a palindrome (96266800866269).
The spelling of 20055500311267 in words is "twenty trillion, fifty-five billion, five hundred million, three hundred eleven thousand, two hundred sixty-seven".
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