Base | Representation |
---|---|
bin | 11101001100010001100… |
… | …111110000101101101011 |
3 | 21002202221202021010001022 |
4 | 131030101213300231223 |
5 | 230331340103104201 |
6 | 4133321534043055 |
7 | 264634450146152 |
oct | 35142147605553 |
9 | 7082852233038 |
10 | 2006045363051 |
11 | 7038393455a4 |
12 | 28495064948b |
13 | 117227b53a82 |
14 | 6d14370a599 |
15 | 372adac641b |
hex | 1d3119f0b6b |
2006045363051 has 4 divisors (see below), whose sum is σ = 2006055694752. Its totient is φ = 2006035031352.
The previous prime is 2006045363029. The next prime is 2006045363057. The reversal of 2006045363051 is 1503635406002.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2006045363051 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2006045363057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4868915 + ... + 5264828.
It is an arithmetic number, because the mean of its divisors is an integer number (501513923688).
Almost surely, 22006045363051 is an apocalyptic number.
2006045363051 is a deficient number, since it is larger than the sum of its proper divisors (10331701).
2006045363051 is a wasteful number, since it uses less digits than its factorization.
2006045363051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10331700.
The product of its (nonzero) digits is 64800, while the sum is 35.
It can be divided in two parts, 200604 and 5363051, that added together give a palindrome (5563655).
The spelling of 2006045363051 in words is "two trillion, six billion, forty-five million, three hundred sixty-three thousand, fifty-one".
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