201101010121113 has 4 divisors (see below), whose sum is σ = 268134680161488. Its totient is φ = 134067340080740.

The previous prime is 201101010121111. The next prime is 201101010121127. The reversal of 201101010121113 is 311121010101102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201101010121113 - 2¹ = 201101010121111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 201101010121092 and 201101010121101.

It is not an unprimeable number, because it can be changed into a prime (201101010121111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33516835020183 + ... + 33516835020188.

It is an arithmetic number, because the mean of its divisors is an integer number (67033670040372).

Almost surely, 2^{201101010121113} is an apocalyptic number.

It is an amenable number.

201101010121113 is a deficient number, since it is larger than the sum of its proper divisors (67033670040375).

201101010121113 is an equidigital number, since it uses as much as digits as its factorization.

201101010121113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67033670040374.

The product of its (nonzero) digits is 12, while the sum is 15.

Adding to 201101010121113 its reverse (311121010101102), we get a palindrome (512222020222215).

The spelling of 201101010121113 in words is "two hundred one trillion, one hundred one billion, ten million, one hundred twenty-one thousand, one hundred thirteen".