20110311314011 has 4 divisors (see below), whose sum is σ = 20364872216800. Its totient is φ = 19855750411224.

The previous prime is 20110311313999. The next prime is 20110311314029. The reversal of 20110311314011 is 11041311301102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20110311314011 - 2²¹ = 20110309216859 is a prime.

It is a super-2 number, since 2×20110311314011² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20110311314011.

It is not an unprimeable number, because it can be changed into a prime (20110311354011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127280451276 + ... + 127280451433.

It is an arithmetic number, because the mean of its divisors is an integer number (5091218054200).

Almost surely, 2^{20110311314011} is an apocalyptic number.

20110311314011 is a deficient number, since it is larger than the sum of its proper divisors (254560902789).

20110311314011 is an equidigital number, since it uses as much as digits as its factorization.

20110311314011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 254560902788.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 20110311314011 its reverse (11041311301102), we get a palindrome (31151622615113).

The spelling of 20110311314011 in words is "twenty trillion, one hundred ten billion, three hundred eleven million, three hundred fourteen thousand, eleven".