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2011112231331 = 3795767249111
BaseRepresentation
bin11101010000111111101…
…000010101000110100011
321010021000212110200122110
4131100333220111012203
5230422224212400311
64135520414410403
7265204143624660
oct35207750250643
97107025420573
102011112231331
117059a9474745
12285925500a03
131178547c5898
146d4a4616a67
15374a883a8a6
hex1d43fa151a3

2011112231331 has 8 divisors (see below), whose sum is σ = 3064551971584. Its totient is φ = 1149206989320.

The previous prime is 2011112231309. The next prime is 2011112231393. The reversal of 2011112231331 is 1331322111102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2011112231331 - 221 = 2011110134179 is a prime.

It is a super-2 number, since 2×20111122313312 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 95767249111 = 2011112231331 / (2 + 0 + 1 + 1 + 1 + 1 + 2 + 2 + 3 + 1 + 3 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2011112231298 and 2011112231307.

It is not an unprimeable number, because it can be changed into a prime (2011112231731) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47883624535 + ... + 47883624576.

It is an arithmetic number, because the mean of its divisors is an integer number (383068996448).

Almost surely, 22011112231331 is an apocalyptic number.

2011112231331 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

2011112231331 is a deficient number, since it is larger than the sum of its proper divisors (1053439740253).

2011112231331 is an equidigital number, since it uses as much as digits as its factorization.

2011112231331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95767249121.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 2011112231331 its reverse (1331322111102), we get a palindrome (3342434342433).

The spelling of 2011112231331 in words is "two trillion, eleven billion, one hundred twelve million, two hundred thirty-one thousand, three hundred thirty-one".

Divisors: 1 3 7 21 95767249111 287301747333 670370743777 2011112231331