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201112011403 = 4332531437757
BaseRepresentation
bin1011101101001100110…
…1011100001010001011
3201020002211201201100221
42323103031130022023
511243334133331103
6232220052210511
720346512614522
oct2732315341213
9636084651327
10201112011403
117832253a896
1232b88009a37
1315c708170a4
149a3ba694b9
155370dce1bd
hex2ed335c28b

201112011403 has 8 divisors (see below), whose sum is σ = 205852439408. Its totient is φ = 196374465504.

The previous prime is 201112011367. The next prime is 201112011427. The reversal of 201112011403 is 304110211102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-201112011403 is a prime.

It is a super-2 number, since 2×2011120114032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201112011103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 579000 + ... + 858757.

It is an arithmetic number, because the mean of its divisors is an integer number (25731554926).

Almost surely, 2201112011403 is an apocalyptic number.

201112011403 is a deficient number, since it is larger than the sum of its proper divisors (4740428005).

201112011403 is a wasteful number, since it uses less digits than its factorization.

201112011403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1441053.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 201112011403 its reverse (304110211102), we get a palindrome (505222222505).

The spelling of 201112011403 in words is "two hundred one billion, one hundred twelve million, eleven thousand, four hundred three".

Divisors: 1 43 3253 139879 1437757 61823551 4677023521 201112011403