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20111214115 = 517236602519
BaseRepresentation
bin10010101110101110…
…001100011000100011
31220220120210112100001
4102232232030120203
5312141432322430
613123341040431
71311242333206
oct225656143043
956816715301
1020111214115
11859028a913
123a93256117
131b867467c5
14d8ad9593d
157ca8d83ca
hex4aeb8c623

20111214115 has 8 divisors (see below), whose sum is σ = 25553072160. Its totient is φ = 15142561152.

The previous prime is 20111214103. The next prime is 20111214143. The reversal of 20111214115 is 51141211102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20111214115 - 229 = 19574343203 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20111214092 and 20111214101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 118301175 + ... + 118301344.

It is an arithmetic number, because the mean of its divisors is an integer number (3194134020).

Almost surely, 220111214115 is an apocalyptic number.

20111214115 is a deficient number, since it is larger than the sum of its proper divisors (5441858045).

20111214115 is a wasteful number, since it uses less digits than its factorization.

20111214115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 236602541.

The product of its (nonzero) digits is 80, while the sum is 19.

Adding to 20111214115 its reverse (51141211102), we get a palindrome (71252425217).

The spelling of 20111214115 in words is "twenty billion, one hundred eleven million, two hundred fourteen thousand, one hundred fifteen".

Divisors: 1 5 17 85 236602519 1183012595 4022242823 20111214115