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201113352003 = 367037784001
BaseRepresentation
bin1011101101001101001…
…0100011011101000011
3201020002221020211022210
42323103102203131003
511243340004231003
6232220141033203
720346530200134
oct2732322433503
9636087224283
10201113352003
1178323276023
1232b88555803
1315c70b96345
149a3bcd7c8b
155371096503
hex2ed34a3743

201113352003 has 4 divisors (see below), whose sum is σ = 268151136008. Its totient is φ = 134075568000.

The previous prime is 201113351993. The next prime is 201113352029. The reversal of 201113352003 is 300253311102.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 201113352003 - 212 = 201113347907 is a prime.

It is a super-2 number, since 2×2011133520032 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (201113352053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33518891998 + ... + 33518892003.

It is an arithmetic number, because the mean of its divisors is an integer number (67037784002).

Almost surely, 2201113352003 is an apocalyptic number.

201113352003 is a deficient number, since it is larger than the sum of its proper divisors (67037784005).

201113352003 is an equidigital number, since it uses as much as digits as its factorization.

201113352003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67037784004.

The product of its (nonzero) digits is 540, while the sum is 21.

Adding to 201113352003 its reverse (300253311102), we get a palindrome (501366663105).

The spelling of 201113352003 in words is "two hundred one billion, one hundred thirteen million, three hundred fifty-two thousand, three".

Divisors: 1 3 67037784001 201113352003