2011221100121 has 4 divisors (see below), whose sum is σ = 2033819090100. Its totient is φ = 1988623110144.

The previous prime is 2011221100081. The next prime is 2011221100139. The reversal of 2011221100121 is 1210011221102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 367533000025 + 1643688100096 = 606245^2 + 1282064^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2011221100121 is a prime.

It is a super-4 number, since 4×2011221100121⁴ (a number of 50 digits) contains 4444 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2011221100096 and 2011221100105.

It is not an unprimeable number, because it can be changed into a prime (2011221100151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11298994856 + ... + 11298995033.

It is an arithmetic number, because the mean of its divisors is an integer number (508454772525).

Almost surely, 2^{2011221100121} is an apocalyptic number.

It is an amenable number.

2011221100121 is a deficient number, since it is larger than the sum of its proper divisors (22597989979).

2011221100121 is an equidigital number, since it uses as much as digits as its factorization.

2011221100121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22597989978.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 2011221100121 its reverse (1210011221102), we get a palindrome (3221232321223).

The spelling of 2011221100121 in words is "two trillion, eleven billion, two hundred twenty-one million, one hundred thousand, one hundred twenty-one".