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2011224013241 = 3675480174423
BaseRepresentation
bin11101010001000110010…
…010101111100110111001
321010021022122210210121012
4131101012102233212321
5230422441321410431
64135535450323305
7265210002020522
oct35210622574671
97107278723535
102011224013241
11705a56583093
12285956a29535
13117871a03021
146d4b53d3849
15374b356b22b
hex1d4464af9b9

2011224013241 has 4 divisors (see below), whose sum is σ = 2016704188032. Its totient is φ = 2005743838452.

The previous prime is 2011224013213. The next prime is 2011224013273. The reversal of 2011224013241 is 1423104221102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2011224013241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2011224010241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2740086845 + ... + 2740087578.

It is an arithmetic number, because the mean of its divisors is an integer number (504176047008).

Almost surely, 22011224013241 is an apocalyptic number.

It is an amenable number.

2011224013241 is a deficient number, since it is larger than the sum of its proper divisors (5480174791).

2011224013241 is an equidigital number, since it uses as much as digits as its factorization.

2011224013241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5480174790.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 2011224013241 its reverse (1423104221102), we get a palindrome (3434328234343).

The spelling of 2011224013241 in words is "two trillion, eleven billion, two hundred twenty-four million, thirteen thousand, two hundred forty-one".

Divisors: 1 367 5480174423 2011224013241