Base | Representation |
---|---|
bin | 101101101110101110111000… |
… | …001110101000101001010011 |
3 | 222101010012222020000212201001 |
4 | 231232232320032220221103 |
5 | 202330201434222222120 |
6 | 1551430512132522431 |
7 | 60235460266260526 |
oct | 5556567016505123 |
9 | 871105866025631 |
10 | 201123524414035 |
11 | 590a200a285833 |
12 | 1a683105480417 |
13 | 882bb36978972 |
14 | 37946054c8bbd |
15 | 183ba3eddbe0a |
hex | b6ebb83a8a53 |
201123524414035 has 16 divisors (see below), whose sum is σ = 244655115078240. Its totient is φ = 158694242446080.
The previous prime is 201123524413951. The next prime is 201123524414123. The reversal of 201123524414035 is 530414425321102.
It is not a de Polignac number, because 201123524414035 - 221 = 201123522316883 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201123524413985 and 201123524414003.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 162604225 + ... + 163836445.
It is an arithmetic number, because the mean of its divisors is an integer number (15290944692390).
Almost surely, 2201123524414035 is an apocalyptic number.
201123524414035 is a deficient number, since it is larger than the sum of its proper divisors (43531590664205).
201123524414035 is a wasteful number, since it uses less digits than its factorization.
201123524414035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1679478.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 201123524414035 its reverse (530414425321102), we get a palindrome (731537949735137).
The spelling of 201123524414035 in words is "two hundred one trillion, one hundred twenty-three billion, five hundred twenty-four million, four hundred fourteen thousand, thirty-five".
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