20112413232433 has 4 divisors (see below), whose sum is σ = 20136385120320. Its totient is φ = 20088441344548.

The previous prime is 20112413232413. The next prime is 20112413232463. The reversal of 20112413232433 is 33423231421102.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-20112413232433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 20112413232395 and 20112413232404.

It is not an unprimeable number, because it can be changed into a prime (20112413232413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11985942685 + ... + 11985944362.

It is an arithmetic number, because the mean of its divisors is an integer number (5034096280080).

Almost surely, 2^{20112413232433} is an apocalyptic number.

It is an amenable number.

20112413232433 is a deficient number, since it is larger than the sum of its proper divisors (23971887887).

20112413232433 is an equidigital number, since it uses as much as digits as its factorization.

20112413232433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23971887886.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 20112413232433 its reverse (33423231421102), we get a palindrome (53535644653535).

The spelling of 20112413232433 in words is "twenty trillion, one hundred twelve billion, four hundred thirteen million, two hundred thirty-two thousand, four hundred thirty-three".