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20113140433 = 57734858129
BaseRepresentation
bin10010101110110101…
…100010101011010001
31220220201102101202011
4102232311202223101
5312142430443213
613123450222521
71311264605251
oct225665425321
956821371664
1020113140433
118591386111
123a93a24a41
131b86c6c539
14d8b337961
157cab6903d
hex4aed62ad1

20113140433 has 4 divisors (see below), whose sum is σ = 20147999140. Its totient is φ = 20078281728.

The previous prime is 20113140373. The next prime is 20113140449. The reversal of 20113140433 is 33404131102.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 17729455104 + 2383685329 = 133152^2 + 48823^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20113140433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (20113140233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17428488 + ... + 17429641.

It is an arithmetic number, because the mean of its divisors is an integer number (5036999785).

Almost surely, 220113140433 is an apocalyptic number.

It is an amenable number.

20113140433 is a deficient number, since it is larger than the sum of its proper divisors (34858707).

20113140433 is an equidigital number, since it uses as much as digits as its factorization.

20113140433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34858706.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 20113140433 its reverse (33404131102), we get a palindrome (53517271535).

The spelling of 20113140433 in words is "twenty billion, one hundred thirteen million, one hundred forty thousand, four hundred thirty-three".

Divisors: 1 577 34858129 20113140433