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2011314251 = 17118312603
BaseRepresentation
bin111011111100010…
…0011100001001011
312012011122100110102
41313320203201023
513104344024001
6531325240015
7100561613642
oct16770434113
95164570412
102011314251
11942375191
1248170300b
1326090919b
141511a2359
15bb899e6b
hex77e2384b

2011314251 has 4 divisors (see below), whose sum is σ = 2129626872. Its totient is φ = 1893001632.

The previous prime is 2011314247. The next prime is 2011314257. The reversal of 2011314251 is 1524131102.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2011314251 - 22 = 2011314247 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2011314257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59156285 + ... + 59156318.

It is an arithmetic number, because the mean of its divisors is an integer number (532406718).

Almost surely, 22011314251 is an apocalyptic number.

2011314251 is a deficient number, since it is larger than the sum of its proper divisors (118312621).

2011314251 is a wasteful number, since it uses less digits than its factorization.

2011314251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118312620.

The product of its (nonzero) digits is 240, while the sum is 20.

The square root of 2011314251 is about 44847.6783234093. The cubic root of 2011314251 is about 1262.2924276066.

Adding to 2011314251 its reverse (1524131102), we get a palindrome (3535445353).

The spelling of 2011314251 in words is "two billion, eleven million, three hundred fourteen thousand, two hundred fifty-one".

Divisors: 1 17 118312603 2011314251