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20113302035 = 530829130483
BaseRepresentation
bin10010101110110110…
…001010001000010011
31220220201201121102102
4102232312022020103
5312143001131120
613123453511015
71311266150351
oct225666121023
956821647372
1020113302035
118591486572
123a93aa246b
131b86cc7c68
14d8b37a7d1
157cab9bd75
hex4aed8a213

20113302035 has 8 divisors (see below), whose sum is σ = 24136930320. Its totient is φ = 16089996384.

The previous prime is 20113302029. The next prime is 20113302047. The reversal of 20113302035 is 53020331102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 20113302035 - 210 = 20113301011 is a prime.

It is a super-2 number, since 2×201133020352 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 20113301998 and 20113302016.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 88904 + ... + 219386.

It is an arithmetic number, because the mean of its divisors is an integer number (3017116290).

Almost surely, 220113302035 is an apocalyptic number.

20113302035 is a deficient number, since it is larger than the sum of its proper divisors (4023628285).

20113302035 is a wasteful number, since it uses less digits than its factorization.

20113302035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161317.

The product of its (nonzero) digits is 540, while the sum is 20.

Adding to 20113302035 its reverse (53020331102), we get a palindrome (73133633137).

The spelling of 20113302035 in words is "twenty billion, one hundred thirteen million, three hundred two thousand, thirty-five".

Divisors: 1 5 30829 130483 154145 652415 4022660407 20113302035